It stays the same.
V = N*d(BA)/dt = N*w*BA = N*2w*0.5BA
(Faraday’s law, ref.)
what happens to the peak emf of a generator if the rotational speed is doubled and the magnetic field halved?
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It stays the same.
V = N*d(BA)/dt = N*w*BA = N*2w*0.5BA
(Faraday’s law, ref.)
March 8th, 2010 at 3:40 am
It stays the same.
V = N*d(BA)/dt = N*w*BA = N*2w*0.5BA
(Faraday’s law, ref.)
References :
http://hyperphysics.phy-astr.gsu.edu/HBASE/electric/farlaw.html